Mohr’s Circle Calculator for Principal Stresses


Mohr’s Circle Calculator for Principal Stresses

An engineering tool to visualize stress transformation and find principal stresses for a 2D plane stress state.



Enter the normal stress acting on the X-face. Tensile is positive, compressive is negative.


Enter the normal stress acting on the Y-face.


Enter the shear stress. Positive if it causes clockwise rotation of the element.


Select the unit for all stress inputs.


Principal Stresses

σ₁ = 92.4 MPa

σ₂ = -72.4 MPa


Maximum Shear Stress (τₘₐₓ): 82.4 MPa

Center of Circle (σₐᵥₑ): 10.0 MPa

Radius of Circle (R): 82.4 MPa

Angle of Principal Plane (θₚ): 14.9 °

Figure 1: Graphical representation of Mohr’s Circle based on input stresses. The horizontal axis is Normal Stress (σ) and the vertical axis is Shear Stress (τ).


Table 1: Summary of Calculated Stress Results
Parameter Value Unit

What is Mohr’s Circle for Principal Stresses?

Mohr’s Circle is a graphical method, developed by Christian Otto Mohr, used in engineering and physics to visualize the transformation of a 2D stress state. When an object is under load, stresses act on it in different directions. Mohr’s Circle allows us to easily determine the most critical stresses at any point within that object: the **principal stresses**. These are the maximum and minimum normal stresses acting on a body, and they occur on planes where the shear stress is zero. Understanding these values is fundamental to structural design and material science, as materials often fail due to maximum stresses. This calculator helps you **calculate Mohr’s Circle and the resulting principal stresses** from a given set of initial stress components.

The Formulas to Calculate Mohr’s Circle and Principal Stresses

The calculations are based on the stress components on a small element at a point: normal stress in the x-direction (σₓ), normal stress in the y-direction (σᵧ), and the shear stress (τₓᵧ). From these inputs, we can construct the circle and find the key values.

  • Center of the Circle (Average Normal Stress): The circle’s center lies on the normal stress axis (the x-axis) at a value equal to the average of the normal stresses.

    σₐᵥₑ = (σₓ + σᵧ) / 2
  • Radius of the Circle: The radius of the circle determines the magnitude of the maximum shear stress.

    R = sqrt[ ((σₓ - σᵧ) / 2)² + τₓᵧ² ]
  • Principal Stresses (σ₁ and σ₂): These are the points where the circle intersects the normal stress axis. They represent the maximum and minimum normal stresses.

    σ₁ (max) = σₐᵥₑ + R

    σ₂ (min) = σₐᵥₑ - R
  • Maximum Shear Stress (τₘₐₓ): This is equal to the radius of the circle.

    τₘₐₓ = R
  • Angle of the Principal Plane (θₚ): This is the angle from the original x-axis to the plane where the principal stress σ₁ acts. The angle on Mohr’s circle is 2θₚ.

    tan(2θₚ) = 2 * τₓᵧ / (σₓ - σᵧ)

Variables Explained

Table 2: Input and Output Variable Definitions
Variable Meaning Unit Typical Range
σₓ Normal stress in the x-direction MPa, psi, etc. -1000 to 1000
σᵧ Normal stress in the y-direction MPa, psi, etc. -1000 to 1000
τₓᵧ Shear stress on the xy-plane MPa, psi, etc. -1000 to 1000
σ₁, σ₂ Principal normal stresses (max and min) MPa, psi, etc. Depends on inputs
τₘₐₓ Maximum in-plane shear stress MPa, psi, etc. Depends on inputs
θₚ Angle to the principal plane Degrees -90° to 90°

Practical Examples

Example 1: Combined Tension and Shear

Imagine a point on a steel beam subjected to tensile and shear forces, resulting in the following stress state:

  • Inputs: σₓ = 100 MPa, σᵧ = 20 MPa, τₓᵧ = 45 MPa
  • Calculation:
    • Center (σₐᵥₑ) = (100 + 20) / 2 = 60 MPa
    • Radius (R) = sqrt[ ((100 – 20) / 2)² + 45² ] = sqrt[ 40² + 45² ] = 60.2 MPa
  • Results:
    • Principal Stress σ₁ = 60 + 60.2 = 120.2 MPa
    • Principal Stress σ₂ = 60 – 60.2 = -0.2 MPa
    • Maximum Shear Stress τₘₐₓ = 60.2 MPa

Example 2: Compression and Shear

Consider a concrete column under a compressive load that also experiences some torsional shear:

  • Inputs: σₓ = -50 MPa, σᵧ = -10 MPa, τₓᵧ = -25 MPa
  • Calculation:
    • Center (σₐᵥₑ) = (-50 – 10) / 2 = -30 MPa
    • Radius (R) = sqrt[ ((-50 – (-10)) / 2)² + (-25)² ] = sqrt[ (-20)² + (-25)² ] = 32.0 MPa
  • Results:
    • Principal Stress σ₁ = -30 + 32.0 = 2.0 MPa
    • Principal Stress σ₂ = -30 – 32.0 = -62.0 MPa
    • Maximum Shear Stress τₘₐₓ = 32.0 MPa

How to Use This Mohr’s Circle Calculator

Using this calculator is a straightforward process to determine principal stresses.

  1. Enter Stress Values: Input your known stress values for σₓ, σᵧ, and τₓᵧ into the designated fields. Remember that tension is positive and compression is negative.
  2. Select Units: Choose the appropriate unit of stress (e.g., MPa, psi) from the dropdown menu. All your inputs should be in this same unit.
  3. Interpret the Results: The calculator will instantly update. The “Principal Stresses” section shows the main output: σ₁ (maximum) and σ₂ (minimum). You can also see important intermediate values like the maximum shear stress and the circle’s center and radius.
  4. Analyze the Graph: The canvas displays the Mohr’s Circle plot. The points where the circle crosses the horizontal axis are your principal stresses. The highest point on the circle corresponds to the maximum shear stress.

Key Factors That Affect Principal Stresses

The resulting principal stresses are highly sensitive to the initial stress state. Here are the key factors:

  • Magnitude of Normal Stresses (σₓ, σᵧ): Changing these values shifts the circle’s center left or right and alters its radius. A large difference between σₓ and σᵧ increases the circle’s diameter.
  • Magnitude of Shear Stress (τₓᵧ): The shear stress directly controls the radius of the circle. A higher shear stress leads to a larger circle and, consequently, a greater difference between the principal stresses and a higher maximum shear stress. If τₓᵧ is zero, the initial stresses are already the principal stresses.
  • Sign of Stresses: Whether the stresses are tensile (positive) or compressive (negative) determines the position of the circle on the normal stress axis. A fully compressive state will place the circle entirely on the negative side.
  • Relative Magnitudes: The interplay between all three input stresses determines the final outcome. A small shear stress might be negligible if the normal stresses are huge, and vice-versa.
  • Material Properties: While the calculation of principal stresses is independent of the material, their significance is not. The calculated σ₁ is compared against the material’s tensile strength (like the data found in a Material Properties Database) to predict failure.
  • Loading Type: The type of load (e.g., uniaxial tension, pure torsion, bending) determines the initial stress state. For example, in pure torsion, σₓ and σᵧ are zero, and the circle is centered at the origin.

Frequently Asked Questions (FAQ)

What is a principal plane?

A principal plane is a plane within a stressed object where the shear stress is zero. Only normal stresses (the principal stresses) act on these planes. There are at least two such planes, and they are always perpendicular to each other.

Why is the shear stress plotted downwards for positive values on some diagrams?

This is a common sign convention. Plotting positive shear (clockwise rotation) downwards makes the angle 2θ on the circle have the same direction (counter-clockwise) as the angle θ on the physical element. This calculator uses the standard mathematical convention (Y-axis positive upwards) but the angle calculation remains correct.

What happens if my shear stress (τₓᵧ) is zero?

If τₓᵧ = 0, your initial normal stresses (σₓ and σᵧ) are already the principal stresses. The Mohr’s Circle will be centered at (σₓ + σᵧ)/2 and its radius will be |σₓ – σᵧ|/2. The points representing the stress state are already on the horizontal axis.

Can a principal stress be negative?

Yes. A negative principal stress indicates that the maximum or minimum normal stress is compressive. It’s common to have one positive (tensile) and one negative (compressive) principal stress.

What is the difference between maximum in-plane shear stress and absolute maximum shear stress?

This calculator determines the maximum *in-plane* shear stress for a 2D stress state (τₘₐₓ = R). In a 3D analysis, you also consider the third principal stress (often zero in plane stress problems). The absolute maximum shear stress is the largest of (σ₁-σ₂)/2, (σ₁-σ₃)/2, or (σ₂-σ₃)/2. For many cases where σ₁ is positive and σ₂ is negative, the in-plane value is the absolute maximum.

How does this relate to a Yield Strength Calculator?

This calculator finds the stresses acting on a point. A yield strength calculator, often using theories like Von Mises or Tresca, takes these principal stresses as inputs to determine if the material will yield or fail under that combined stress state.

Does changing the units affect the shape of the circle?

No, changing units (e.g., from MPa to psi) only scales the values of the axes, the center, and the radius. The geometric shape and the orientation angle (θₚ) remain identical. This tool handles the conversion automatically.

What does the angle θₚ tell me?

It tells you how to rotate your point of view from the original x-y axes to see the principal stresses. A positive θₚ means you need to rotate counter-clockwise from the x-axis to find the plane where σ₁ acts. A tool like a Stress Transformation Calculator can show stresses at any angle, not just the principal ones.

© 2026 Your Website Name. All Rights Reserved. For educational and professional use.



Leave a Reply

Your email address will not be published. Required fields are marked *